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Finding the Integrating Factor

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Solve for "c"
(3y^2+2xy)dx-(2xy+x^2)dy =0

I see that the equation is not exact. Differentiate the 1st side by My and the second by Nx. which gives me My=6y+2x and Nx= 2y+2x
I add these together and divide by the "N" term and come up with an integrating factor of x^4. This still doesn't make the equation exact.

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Solution Summary

The solution decides the integrating factor.

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