# Evaluate the Surface Integral

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Evaluate the surface integral SSs x dS, where S is part of the plane x = 2y = 3z = 6 that lies in the first octant.

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##### Solution Summary

A surface integral is evaluated.

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Surface integral of x.dS over S where S is part of the plane x+2y+3z= 6 which lies in the first octant.

The surface integral can be transformed into a double integral over R (in the the cartesian plane).

x+2y+3z = 6

Write z = F(x,y) = ...

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