Evaluate the Surface Integral
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Evaluate the surface integral SSs x dS, where S is part of the plane x = 2y = 3z = 6 that lies in the first octant.
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Solution Summary
A surface integral is evaluated.
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Surface integral of x.dS over S where S is part of the plane x+2y+3z= 6 which lies in the first octant.
The surface integral can be transformed into a double integral over R (in the the cartesian plane).
x+2y+3z = 6
Write z = F(x,y) = ...
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