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Graph parabola

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Y=x^2-6x+8 in to the form y=a(x-h)^2+k

How do you change the function?

This initial problem is followed by:
a) What is the equation for the line of symmetry for the graph of the function.
(I think I can solve this )

Please explain and show in detail how to break this down in (dummy language)

b) Asks that the function be graphed based on the initial form of y=a(x-h)^2+k
I know how to graph it once I can solve it.) Why do you not have to plot points when using:
y=a(x-h)^2+k
And note how this graph compares to the graph of y=x^2

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Solution Summary

The detailed solution elaborates on how to graph the parabola by its basic properties, such as, axis of symmetry, vertex, x- and y-intercepts. It also explains the transformation of parabola functions both mathematically and graphically.

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