Find the Equation for a Tangent Line
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Find an equation of the line tangent to the curve defined by the equation at the specified point:
x^2/3 + y^2/3 = 2; (1,1)
(^means exponent and 2/3 is the exponent)
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Solution Summary
This shows how to find the tangent line at a given point.
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x^2/3 + y^2/3 = 2; (1,1)
to find slope:
dy/dx==>
d(x^m)/dy = m (x^m-1)
2/3 x^( 2/3-1) + ...
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