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Find the Equation for a Tangent Line

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Please explain the steps and solution, thanks:

Find an equation of the line tangent to the curve defined by the equation at the specified point:

x^2/3 + y^2/3 = 2; (1,1)

(^means exponent and 2/3 is the exponent)

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Solution Summary

This shows how to find the tangent line at a given point.

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x^2/3 + y^2/3 = 2; (1,1)

to find slope:
dy/dx==>
d(x^m)/dy = m (x^m-1)

2/3 x^( 2/3-1) + ...

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