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    Continuous Functions

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    Where is the function

    f(x) = (q^2 - 1)/q^2 if x = p/q meaning x is a rational in reduced form and f(x) = 1 when x is not a rational

    continuous in the interval (0,1)? Please also explain how you came up with the answer.

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    https://brainmass.com/math/graphs-and-functions/continuous-functions-8952

    Solution Preview

    Solution.

    (1) Let x0=p/q be a point in the interval (0,1) and x0 is an rational. By the definition of f(x), we know that
    f(x0)=(q^2-1)/q^2. Obviously, f(x0)<1.
    Since the irrational is dense in (0,1), we can choose a sequence y1,y2,...,yn,... such that yn->x0 and yi are irrational numbers for all i=1,2,....

    By the definition of f(x), we have f(yi)=1 for i=1,2,...,
    So, f(yn)->1 as n tends to infinity, which implies that the limit of f(x) (as x tends to x0=p/q) is not equal to f(x0)=(q^2-1)/q^2 if the limit of f(x) (as x->x0) exists.

    So, by the ...

    Solution Summary

    The continuity of a given function is investigated across an interval.

    $2.49

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