smallest possible value of an angle
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T(A) is defined for A by T(A)= 3cos(A - 60) + 2 cos(A + 60)
I have established that T(A) can be written SQRT(7)sin(A + 70.9), now need to find the smallest possible value of A such that T(A) + 1 = 0.
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The solution finds out the smallest angle that satisfies certain trigonometric relationship.
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Finding smallest possible value of an angle
T(A) is defined for A by T(A)= 3cos(A - 60) + 2 cos(A + 60)
I have established that ...
Purchase this Solution
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