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Find the dimensions of the trapezoid of greatest area with longer base on the x axis and its other two vertices above the x axis and on the graph of 4y = 16 - x^2.

Find the dimensions of the trapezoid of greatest area with longer base on the x axis and its other two vertices above the x axis and on the graph of 4y = 16 - x^2.

keywords: trapezium, trapezoids

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Please see attached file.

Area A = ½*(sum of parallel sides)*Altitude
The base of the trapezium lies between the two points where the parabola cuts the x-axis.
Therefore, 4*0 = 16 - x2 = 0
Or x = 4 or -4.
So the length of the base = 8 ...

Solution Summary

The dimensions of a trapezoid with greatest are is found.

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