# center of gravity of a lamina in the shape of a parallelogram

Prove the the center of gravity of a lamina in the shape of a parallelogram is at the point of intersection of the diagonals and that it is the same point as the center of gravity of four particles two of mass m at one pair of opposite vertices and two of mass 2m at the other pair of opposite vertices.

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#### Solution Summary

Provides steps necessary to prove the center of gravity of a lamina.

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