# Strange Summation

First note that x = Floor(x) + {x}, where {} is the remainder.

So if x= 2.74, then the floor is 2 + the remainder is .74 .

f(x)= { 0 if x its a perfect square (like 1,4,9,...)

{ Floor (1/ {sqrt(x)}) otherwise

So for the otherwise part, say x=2, you have 1/the remainder of sqrt(2), which is 1/.414 = 2.4, then take the floor. So x=2 is 2.

Find: f(1) + f(2) + f(3) + .... + f(256)

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#### Solution Summary

A pattern is detected for the strange summation problem embedded here.

$2.19