There are n trading posts along a river. At any of the posts you can rent a canoe to be returned at any other post downstream. (It is next to impossible to paddle against the current.) For each possible departure point i and each possible arrival point j the cost of a rental from i to j is known. However, it can happen that the cost of renting for i to j is higher that the total cost of a series of shorter rentals. In this case you can return the first canoe at some post k between i and j and continue your journey in a second canoe. There is no extra charge for changing canoes in this way.
Give an efficient algorithm to determine the minimum cost of a trip by canoe for each possible departure point i to each possible arrival point j. In terms of n, how much time is needed by your algorithm?
Let c(i,j) be the cost of a rental directly from i to j. From the condition, it is impossible to paddle against the current. So we always assume i<=j in c(i,j). Moreover, c(i,i)=0.
Suppose the function MinCost(i,j) outputs the minimum cost of a trip by canoe from i to j with (i<=j). We know, ...
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