Purchase Solution

Differentiability

Name: Differentiability
Brand: BrainMass
Price: 2.49 USD
Availability: InStock

Not what you're looking for?

Prove that if f(x) = x^alpha, where alpha = 1/n for some n in N (the natural numbers), then y = f(x) is differentiable and f'(x) = alpha x^(alpha - 1).

Progress I have made so far:

I have managed to prove,

(x^n)' = n x^(n - 1) for n in N and x in R

both from the definition of differentiation involving the limit and the binomial theorem or equivalently using induction on n. Feel free to use this result although anything else should be made rigorous. It should be possible to prove this by the basic definition of the derivative. Thanks!

Purchase this Solution

Solution Summary

Limits are used to prove differentiability.

Solution Preview

We first prove that (x^n)'=nx^(n-1) for all n, where n is a positive integer.

Let f(x)=x^n and n is a positive integer. By the definition of f'(x) we have

f'(x)=Limit{[f(x+h)-f(x)]/h, h->0} (1)

where Limit{[f(x+h)-f(x)]/h, h->0} denotes the limit of ...

Solution provided by:

Changping Wang, MA

Education

BSc , Wuhan Univ. China
MA, Shandong Univ.

Recent Feedback

"Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
"excellent work"
"Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
"Thank you"
"Thank you very much for your valuable time and assistance!"

Purchase this Solution

Free BrainMass Quizzes

Know Your Linear Equations

Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.