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instantaneous rate of change of solar radiation

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The total solar radiation H on a particular surface during an average clear day is given by:
H=5000/T^2+10

where t (-6 < equal to or less than t < equal to or less than 6 ) is the number of hours from noon. Note that 6 a.m. is equivalent to t = -6. Find the instantaneous rate of change of H with respect to t at 3 p.m.

Please help me work this this problem by showing work.

Thanks

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The solution shows how to calculate the instantaneous rate of change of solar radiation by derivative.

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