Share
Explore BrainMass

Derivatives, maxima, minima

1. Find the derivative: f(x) = (x^3-8)^(2/3)

2. Write and equation of the tangent line to the graph of y = f(x) at the point on the graph where x has the indicated value. f(x) = (3x^2 + 5x + 4)(4x + 3), x=0

3. Find the values of any relative extrema: f(x)=1/(x^2-1)

Solution Preview

1. Find the derivative: f(x) = (x^3-8)^(2/3)
f'(x) = (x^3-8)^(2/3) ln(x^3 - 8) = 3x^2(x^3-8)^(2/3) ln(x^3 - 8)

2. Write and equation of the tangent line to the graph of y = f(x) at the point on the ...

Solution Summary

This solution is comprised of a detailed explanation to find the derivative: f(x) = (x^3-8)^(2/3).

$2.19