Explore BrainMass

# Derivatives and concavity

Not what you're looking for? Search our solutions OR ask your own Custom question.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

Find the derivative of f(x)= (3-4x^2)/(x^2-x-6) and then determine intervals of increase/decrease,local max and min values and points of concavity and inflection. Also, please tell me that if the derivative of the function is (4x^2+42x+3)/(x^2-x-6) then do I use the denominator or numerator to determine whether the function is increasing or decreasing?

https://brainmass.com/math/derivatives/derivatives-and-concavity-27932

#### Solution Preview

f(x)= (3-4x^2)/(x^2-x-6)
f' = (-8x) /(x^2-x-6) - (3-4x^2)(2x-1) / (x^2-x-6)^2
= [-8x*(x^2-x-6) - (3-4x^2)(2x-1)] / (x^2-x-6)^2
= [(-8x^3 + 8x^2+48x) + (8x^3-4x^2-6x+3)] / (x^2-x-6)^2
= (4x^2+42x+3)/(x^2-x-6)^2

we will study when does f' = 0
Since (x^2-x-6)^2 >= 0, we only need to care about the numerator.
Set 4x^2+42x+3 =0
Then x = [-42 + ...

#### Solution Summary

This shows how to find the derivative and then determine intervals of increase/decrease,local max and min values and points of concavity and inflection.

\$2.49