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Change in Revenue : Derivative Problem

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The Happy Hound Haven Company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x)= 625+.03x+.0001x^2. Approximate the change in revenue from the sale of one more doghouse when 1000 doghouse are sold. (Make sure to do this using derivatives).

Am I correct?
The derivative is
R'(x) = 0.03+0.002x,
Which approximates the change in revenue from the sale of one more doghouse when x doghouses are sold, therefore if x=1000,
R'(1000)=0.03+2=2.03, which is what we want.

Please check this answer, I think the derivative was taken incorrectly and should be R'(x)=0.3+ 0.0002.

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A change in revenue problem is solved using a derivative.

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The derivative of f(x)=x^n is:


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