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    Change in Revenue : Derivative Problem

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    The Happy Hound Haven Company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x)= 625+.03x+.0001x^2. Approximate the change in revenue from the sale of one more doghouse when 1000 doghouse are sold. (Make sure to do this using derivatives).

    Am I correct?
    The derivative is
    R'(x) = 0.03+0.002x,
    Which approximates the change in revenue from the sale of one more doghouse when x doghouses are sold, therefore if x=1000,
    R'(1000)=0.03+2=2.03, which is what we want.

    Please check this answer, I think the derivative was taken incorrectly and should be R'(x)=0.3+ 0.0002.

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    https://brainmass.com/math/derivatives/change-revenue-derivative-problem-38652

    Solution Preview

    The derivative of f(x)=x^n is:

    f'(x)=n*x^(n-1)

    Thus the ...

    Solution Summary

    A change in revenue problem is solved using a derivative.

    $2.49

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