Two people 1.8m tall walk from each other until they can no longer see each other (due to the curvature of the earth which has a radius of 6378km).
Assuming nothing else blocks their view, how far do they have to walk?
Note. I cant get my head around how this relates to what we've learned about radius and arc length.© BrainMass Inc. brainmass.com December 24, 2021, 4:55 pm ad1c9bdddf
SOLUTION This solution is FREE courtesy of BrainMass!
Let S be the distance between the two people such that after walking through a distance S, they won't be able to see each other.
Let R = 6378Km = 6378000 m be the radius of the earth.
Ler angle ACB = 2Theta (see figure)
We know that,
arc length / radius = angle in radians
Therefore, S/R = 2*theta
or, S = R * 2*theta ....(1)
Now, consider the triangle PCB. (The line CP divides S into two equal parts)
angle PCB = theta
PC = 6378000 - 1.8 = 6377998.2 m
CB = 6378000m
Cos[theta] = base/hypotenuse = 6377998.2/6378000 = 0.9999997
theta = arc cos[0.9999997] = 0.04 degrees
converting it to radians using
180 degree = pi radians
therefore, 0.04 degrees = pi*0.04/180 = 6.978*10^-4 radians
Therefore, theta = 6.978*10^-4 radians
Hence, arc length, S = R * 2 * theta = 6378000 * 2 * 6.978*10^-4
=> S = 8900.85 m
or S = 8.9 Km
That is after travelling a distance of 8.9 Km the two persons will not be able to see each other.
Hope you could follow well. The only concepts we used are the relation of arc length and radius of a circle and the basic trigonometric formulae.© BrainMass Inc. brainmass.com December 24, 2021, 4:55 pm ad1c9bdddf>