Extrema of a Bivariate Function
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Find the extrema of f subject to the stated constraints.
f(x,y) = x - y,
subject to
x^2 - y^2 = 2
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Extrema of a bivariate function are located. The solution is detailed and well presented. The response was given a rating of "5/5" by the student who originally posted the question.
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First lets get the function all in terms of x.
Looking at the constraint:
y^2 = x^2 - 2
y = sqrt(x^2 - 2)
Plugging this into f(x,y) we get:
f(x,y) = x - y = x - sqrt(x^2 - 2)
In order to find extrema of a function we take it's ...
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