# Differentiation : Find Local Extrema of a Function on an Interval

Locate the absolute extrema of the function on the closed interval. f(x) = -x^2 + 3x [0,3] [Answer is minimum at (0,0) and (3,0) and max at (3/2), 9/4)

Locate the absolute extrema of the function on the closed interval. g(t) = t^2/t^+ 3 [-1,1] Answer Min (0,0) Max (-1, 1/4) (1, 1/4)

Locate the absolute extrema of the function on the closed interval. y = e^x sin x [0,pi] Answer: Min: (0,0) (pi,0) Max (3pi/4, square root of 2/2(e^3pi/4)

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Differentiation

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Locate the absolute extrema of the function on the closed interval. f(x) = -x^2 + 3x [0,3] [Answer is minimum at (0,0) amd (3,0) ...

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Local extrema are found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.