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Signed measures

If v is a signed measure, E is v-null if |v|(E)=0

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Proof. "<==" Since |v|(E)=v+(E)+v-(E)=0
v+(E)=v-(E)=0. Since v+ and v- are positive measures, v+(E)=v-(E)=0. So ...

Solution Summary

This is a proof regarding signed measures.

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