Please see the attached file for the fully formatted problem.
For phi E C2[R3 ! R3], curl grad phi = 0. Prove this. The converse is "Poincare's Lemma": if f E C1[R3 --> R3] and if curl f = 0, then f is a gradient, i.e., f = grad for some 2 C2. Try it this way: if f = grad phi, then
phi (x1, x2, x3) = phi(0)+ ....
See why? Be that as it may, this function phi is perfectly well - defined. So start from scratch with this phi taken out of the air and see what it's gradient is, assuming curl f = 0.© BrainMass Inc. brainmass.com February 24, 2021, 2:21 pm ad1c9bdddf
Please see the attached file for the complete solution.
Thanks for using BrainMass.
For . If , then f is a gradient, ie., for some .
Proof. (1) We will prove " If then "
Let . ...
A gradient is found using Poincare's Lemma. The solution is detailed and well presented.