Permutations and Combinations
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A) How many ways can a person select three appetizers and two soups if there are six appetizers and five soups on the dinner menu?
b) Three married couples have bought tickets for six seats in a row for a movie.
i) In how many ways can they be seated? n! = 6 x 5 x 4 x 3 x 2 x 1 = 720
ii) In how many ways can they be seated if each couple is to sit together with the husband to the left of the wife?
iii) In how many ways can they be seated if each couple is to sit together?
iv) In how many ways can they be seated if all the men are to sit together and all the women are to sit together?
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Solution Summary
Permutations and combinations are examined.
Solution Preview
a) 6C3*5C2 = 6! 5! 20*10 = 200
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