A 16-ft ladder leans against a wall. The bottom of the ladder is 5 ft from
the wall at time t = 0 and slides away from the wall at a rate of 3 ft/s.
Find the velocity of the top of the ladder at time t = 1.
a) The textbook response to this question is - sqrt (3) is approximately equal too
-1.732 ft/s. The minus sign
means the top of the ladder is sliding down. Check that the textbook's answer is
b) The speed of sound at sea level using the standard atmosphere is about 340.29
meters per second. There are 3.280840 feet in one meter. Using the assumptions
of this model, find the angle between the ladder and the ground at the time that
the top of the ladder breaks the speed of sound.
c) The speed of light is about 299,792,458 meters per second. There are still
3.280840 feet in one meter. Using the assumptions of this model, find the an-
gle between the ladder and the ground at the time that the top of the ladder moves
at the speed of light.
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The solution is attached ...
Pythagoras theorem is also reiterated in order to solve.