# Particular solution of differential equation : dÂ²y/dxÂ² - y = xe^x

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The differential equation is:

dÂ²y/dxÂ² - y = xe^x

For the first part of the general solution, I got y=Ae^x + Be^-x where a and b are constants.

Now I need to find the particular solution.

Thanks.

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particular solution of differential equation

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How do you find the particular solution of this differential equation? I'm not sure if I need to ...

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The particular solution of a differential equation is found. The solution is detailed and well presented.

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