If a ball is thrown straight up into the air with an initial velocity of 75 ft/s, it height in feet after t second is given by y=75tâ?'16t^2. Find the average velocity for the time period beginning when t=1 and lasting
(i) 0.1 seconds
(ii) 0.01 seconds
(iii) 0.001 seconds
Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1.
On the given Equation, the 2 is an exponent.© BrainMass Inc. brainmass.com December 16, 2022, 7:53 am ad1c9bdddf
y=75t - 16t^2
= (y(1.1) - y(1))/(1.1-1)
= ((75*1.1 - 16*1.1^2) -(75*1 - 16*1^2))/0.1
= 41.4 ...
Instantaneous velocity of the ball is depicted in this tutorial.