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# Finding Zeros of Functions

Find the zero of the linear function f(x)=3x-12

Find the zeros of f(x)=x^2-2x-3

Find the vertex of f(x)=x^2-2x+4

Find the axis of symmetry of f(x)=x^2-2x+4

Find the zeros and state the multiplicity of each for
f(x)=x^2(x+3)(x+1)^4

Find the zeros of f(x)=x^2-8x+12

#### Solution Preview

1. Find the zero of the linear function f(x)=3x-12

Solution:

To find zero of this linear function, we need to plugin f(x) =0 in the above function.

0 = 3x - 12

3x -12 =0

Add 12 on both sides, we get

3x -12 +12 = 12

3x = 12

Divide by 3 on both sides,

X = 4

Therefore, 4 is the zero of the linear function.

2. Find the zeros of f(x)=x^2-2x-3

Solution:

Plugin f(x) =0 in the above function, we get

0 = x^2 -2x -3

X^2 - 2x -3 =0

Factorized the above ...

#### Solution Summary

Zeros of functions are found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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