Finding Zeros of Functions
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Find the zero of the linear function f(x)=3x-12
Find the zeros of f(x)=x^2-2x-3
Find the vertex of f(x)=x^2-2x+4
Find the axis of symmetry of f(x)=x^2-2x+4
Find the zeros and state the multiplicity of each for
f(x)=x^2(x+3)(x+1)^4
Find the zeros of f(x)=x^2-8x+12
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Zeros of functions are found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.
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1. Find the zero of the linear function f(x)=3x-12
Solution:
To find zero of this linear function, we need to plugin f(x) =0 in the above function.
0 = 3x - 12
3x -12 =0
Add 12 on both sides, we get
3x -12 +12 = 12
3x = 12
Divide by 3 on both sides,
X = 4
Therefore, 4 is the zero of the linear function.
2. Find the zeros of f(x)=x^2-2x-3
Solution:
Plugin f(x) =0 in the above function, we get
0 = x^2 -2x -3
X^2 - 2x -3 =0
Factorized the above ...
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