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    Differential equations

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    Solve y in terms of t with initial conditions given.
    a.) (d^2)y/dt^2+3dy/dt+2y=24e^-4t y(0)=10 y'(0)=5

    b.) (d^2)y/dt^2+6dy/dt+9y=0 y(0)=10 y'(0)=0

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    https://brainmass.com/math/calculus-and-analysis/differential-equations-21517

    Solution Summary

    This shows how to solve for y in terms of t with initial conditions given.

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