Differential Equation
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When two chemicals A and B react, 1g of A and 2g of B yield 2g of C and a byproduct. The rate at which C is formed is proportional to the amount of A and B present. Suppose that at the outset there are 50g of A and 90g of B present, and that after 1 hour, 45g of C have been formed.
a) Show that the amount of C that has been formed after t hours is : y(t) = 900[(10/11)^t - 1]/[10(10/11)^t - 9]
b) What is the maximum amount of C that can be obtained by this process?
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Solution Summary
Step by step solution provided. The expert examines two chemicals which react to form a byproduct.
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