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    Differential equations

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    Y' = (x+2)^2e^y with y(1) = 0

    © BrainMass Inc. brainmass.com March 4, 2021, 5:37 pm ad1c9bdddf

    Solution Preview

    You have
    dy/dx=(x+2)^2 * Exp(y)

    Now multiply dx to both sides, so you ...

    Solution Summary

    This shows how to solve a differential equation.