Purchase Solution

Finding the area of the surface from revolving around the x-axis

Not what you're looking for?

Ask Custom Question

Given:
y = -x^2 + 4x

defined on the closed domain [0,4]

a) sketch the graph

b) Revolve the graph about the x-axis. Find the area of the surface obtained.

Attachments
Purchase this Solution
Solution Summary

A surface aof revolution is calculated using integrals. The area of the surface from revolving around the x-axis is examined.

Solution Preview

Please see the attached file for the complete solution.
Thanks for using BrainMass.

The graph is correct. To find the area of ...

Purchase this Solution
Free BrainMass Quizzes
Solving quadratic inequalities

This quiz test you on how well you are familiar with solving quadratic inequalities.

Graphs and Functions

This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.

Probability Quiz

Some questions on probability

Multiplying Complex Numbers

This is a short quiz to check your understanding of multiplication of complex numbers in rectangular form.

Exponential Expressions

In this quiz, you will have a chance to practice basic terminology of exponential expressions and how to evaluate them.

View More Free Quizzes
Related BrainMass Solutions

  • Surface area of solid of revolution

    65533 Surface area of revolving curve Using the formula for the surface area of a revolving curve about the x-axis: S=∫2πy√(1 + (dy/dx)²)dx throughout a,b Find the area of the surface generated by revolving the curve about the

  • Volume and surface area of a solid

    the region bound by the circle (x-a)^2 + y^2 = a^2 is revolved around about the y-axis to generate a solid 1 find the volume 2 find the surface area According to method of washers, the volume of the solid generated by revolving the curve around

  • Finding volume bounded by given curves

    583138 Finding volume bounded by given curves 18. Compute the volume of the solid formed by revolving the region bounded by about (a) the x-axis; (b) y = 4. 20.

  • Surface area of a solid

    110064 Surface area of a solid Identify the definite integral that represents the area of the surface formed by revolving the graph of f (x)= x^3 on the interval [0,1] about the y-axis. Hi, here is the solution...

  • Arc length and surface area

    (dy/dx)2 = (-tan x)2 = (tan x)2 ds = dx ds = dx = dx = sec x dx Arc length = dx = dx Find the area of the surface of revolution generated by revolving the given curve around the indicated axis.

  • Surface Area of a Revolving Curve

    65546 Surface Area of a Revolving Curve Using the formula for the surface area of a revolving curve about the y-axis: S=∫2πx√(1 + (dx/dy)²)dy throughout a,b Find the area of the surface generated by revolving the curve about the y axis within

  • Surface Area of Revolution

    Find the surface area of revolution generated by revolving the region under the curve y=2x on the interval [0,1] about the x-axis.

  • Evaluation of the definite integral

    Answer The area of the surface of the solid obtained by revolving the arc of the curve y = f(x) intercepted between the points whose abscissae are a,b about the x-axis is given by the formula, Surface area ,where required

  • Surface area of revolution

    6877 Surface area of revolution How do I find the surface area obtained by revolving the curve y=x-1 from x=1 to x=4 about the line x= -1? Please see the attached file for the complete solution. Thanks for using BrainMass.

View More Related Solutions