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Solving Polynomials by factorizing

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Factor

1. x^2 + 12x +36 - y^6

2.9y^2 + 12y + 4 - x^2

solve each equation

n^2 + n = 72

(4x + 9)(x - 4)(x + 1) = 0

m^3 = m^2 + 12m

(x + 4)(5x - 1 ) = 0

x^ + 6x - 7 = 0

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Solution Summary

The solution describes the steps in factorizing the given polynomials. It also shows step by step method to convert given word problem into algebraic form and then finding the solutions.

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Solutions

30.x^2 + 12x +36 - y^6
first we can factorize
x^2+12x+36
On splitting middle term we get
x^2+6x+6x+36
=x(x+6)+6(x+6)
=(x+6)*(x+6)
Now put this value in original polynomial
x^2 + 12x +36 - y^6
=(x+6)^2-y^6
y^6 may be written as (y^3)^2
we get
=(x+6)^2-(y^3)^2

We know that (a^2-b^2) =(a+b)(a-b)
Comparing above relation with our polynomial we can write
(x+6)^2-(y^3)^2 = {(x+6)+y^3}*{(x+6)-y^3}=(x+6-y^3)(x+6+y^3)

34.9y^2 + 12y + 4 - x^2
First we can factorize
9y^2 + 12y + 4
On splitting middle terms we get
=9y^2+6y+6y+4
=3y(3y+2)+2(3y+2)
=(3y+2)(3y+2)

Now put this value in original polynomial
9y^2 + 12y + 4 - x^2
=(3y+2)^2-x^2

We know that (a^2-b^2) =(a+b)(a-b)
Comparing above relation with our polynomial we can write
(3y+2)^2-x^2 ={(3y+2)+x}*{(3y+2)-x}=(3y+2+x)(3y+2-x)

Solve each equation

Problem: n^2 + n = 72

Solution:
n^2+n-72=0
Split middle terms in such as a way that their product is -72n^2 and sum is +n
n^2+9n-8n-72=0
n(n+9)-8(n+9)=0
(n+9)(n-8)=0
meaning (n+9)=0 or (n-8)=0 or both
n+9=0 i.e. ...

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  • BEng (Hons) , Birla Institute of Technology and Science, India
  • MSc (Hons) , Birla Institute of Technology and Science, India
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