# Related rates

A particle is moving along the curve y=sqrt x. As the particle passes through the point (4,2), its x-coordinate increases at a rate of 3 cm/s. How fast is the distance from the particle to the origin changing at this instant?

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#### Solution Preview

The distance from the particle to the origin can be written into:

S=SQRT(x^2 + y^2) = SQRT(x^2 + x) since ...

#### Solution Summary

This shows how to find the rate of change of distance from a particle to the origin.

$2.19