# Basic Algebra

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1. Find the value of c ( formula ) C = P/9 if p = 144.

2. Find the perimeter of a triangular postage stamp with sides 2.7, 2.7, and 1.7 centimeters long.Choose from the following.

3. Choose "<", "=", or ">" symbol to make a true statement.

|-5| ..... - (-19)

4. Evaluate the expression.

(9 + 8 . 5)^3

5. Find the area of a triangle with a base of 5.75 centimeters (cm) and a height of 1.5 cm.Choose the correct answer from the following.

6. Remove the parentheses.

- 6(t - 9)

7. Is the statement below true or false?

12^2 + 8(13X - X^2) + 3X = 4X^2 + 107X

8. Solve the formula D = 1/10 bw for the variable b and choose the correct answer from the following.

9. The carpenter in the figure below saws a board into two pieces. He wants one piece to be 4 feet longer than twice the length of the shorter piece. Find the length of each piece if y = 28.

10. Find the midpoint of the line segment PQ.

P(2, 7), Q(5, 11)

11. True or False:

The points (3, 7), (0, 6), and (3, 5) lie on the following line:

y = 1/3x + 6

12. Tell whether the line that passes through the two given points is parallel or perpendicular (or neither) to a line with a slope of -2. Match the points in the left column with the appropriate phrase in the right column. Which one is Parallel, neither parallel nor perpendicular, or perpendicular.

(5,9), (7,5)

(5,9), (7,10)

(5,9), (7,-9)

13. Use point-slope form to determine the equation of the line passing through the two given points. Then write the equation in slope-intercept form.

(6,1), (7,7)

14. Determine the equation of the line that passes through the point (1,2) and is parallel to the line 6 y - 24 x = 5. Select the correct answer in slope-intercept form:

15. Simplify the expression.

(3x^7 n ^-3)^2

16. Evaluate the polynomial function.

f (x) = 4 x 2 - 4 x + 5 for x = 2

17. Do the subtraction.

(7 x 2 y 5 + 5 x y - 7 y 4 ) - (2 x 2 y 5 - 9 xy + 3 y 4 )

18. Find the product.

(3 x - 3)(-5 x + 4)

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Basic algebra problems are solved. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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Please help me out with these problems.

1. Find the value of c ( formula ) C = P/9 if p = 144.

If P=144, then

C=P/9=144/9=16

2. Find the perimeter of a triangular postage stamp with sides 2.7, 2.7, and 1.7 centimeters long. Choose from the following.

The perimeter of a triangular postage stamp with sides 2.7, 2.7, and 1.7 centimeters long is equal

2.7+2.7+1.7=7.1 (cm)

3. Choose "<", "=", or ">" symbol to make a true statement.

|-5| ..... - (-19)

As |-5|=5 and -(-19)=19, we conclude that

|-5| < - (-19)

4. Evaluate the expression.

(9 + 8 . 5)^3

Solution.

5. Find the area of a triangle with a base of 5.75 centimeters (cm) and a height of 1.5 cm. Choose the correct answer from the following.

The area is equal ...

###### Education

- BSc , Wuhan Univ. China
- MA, Shandong Univ.

###### Recent Feedback

- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
- "excellent work"
- "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
- "Thank you"
- "Thank you very much for your valuable time and assistance!"

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