Solving Logarithmic Equations
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A) Solve the equation:
log3 (2 - 3x) = log9 (6x2 - 19x + 2)
b) Prove that if a^x = b^y = (ab)^xy, then:
x + y = 1.
See the attached file.
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Solution Preview
Please see the attached file for the complete solution.
a) Solve the equation:
log3 (2 - 3x) = log9 (6x2 - 19x + 2)
Solution:
We know that logxy = log y / log x [Base rule]
Then:
log3(2 - 3x) = log9(6x^2 - 19x +2)
log(2 - 3x) / log 3 = log(6x^2 - 19x +2) / log ...
Solution Summary
A logarithmic equation is solved in the solution.
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