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Solving First Order Algebra Equations

I need some help on some of the questions I am stumped on. Solve the equations showing how you came up with the answer step by step.

(3/4)q-12=4

(1/3)a-6=(2/3)a+6

d+5(d-7)=2d-4(-d-8)

3q+4aw=-2aw+7q+2 Solve for q

d+5d(d-7)=2d-4(-d-8)

Solution Preview

1. (3/4)q-12=4

Add 12 to both sides of the equation
(3/4)q = 4 + 12

Combine terms
(3/4)q = 16

Multiply both sides by 4
3q = 16*4

Divide both sides by 3
3q = 64

q = 64/3

2. (1/3)a-6=(2/3)a+6

multiply through by 3
a-(3)6=(2)a+(3)6
a-18 = 2a +18

add "-a" to both sides of the equation
-18 = a + 18

solve for a
a = -36

3. ...

Solution Summary

Equations are solved step by step.

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