Solving Algebraic Equations for a Given Variable

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• Solving Algebraic Equations for a Given Variable

  36947 Solving Algebraic Equations for a Given Variable Make p the subject of this equation 2p - 3t/5 = k 2p - 3t/5 = k then 2p = 3t/5 +k, dividing both sides of 2, we have p=3t/10+k/2 An algebraic equation is solved for a given variable.

• Solving Algebraic Equations for a Given Variable.

  37002 Solving Algebraic Equations for a Given Variable Solve equation for m 4m/12 + 5/6 = m/2 + 3/8 4m/12 + 5/6 = m/2 + 3/8 =>m/2-m/3=5/6-3/8 =>m/6=11/24 =>m=11/4 An algebraic equation is solved for a given variable.

• Solving Algebraic Equations for a Given Variable

  45974 Solving Algebraic Equations for a Given Variable Solve for x: x + 8 x - 8 -------- - -------- = 2 5 7 x + 8 x - 8 -------- - -------- = 2 5 7 Multiplying throughout

• Discussion questions on systems of linear equations

  Show examples for each possible situation. 2.Is there a difference between solving a system of equations by the algebraic method and the graphical method? Why? What are the advantages and disadvantages of each?

• Solving Algebraic Equations for a Given Variable :sample question

  39850 Solving Algebraic Equations for a Given Variable Question I am trying to solve and check for extraneous solutions x + 2 = root x^2 + 6. x + 2 = root (x^2 + 6) sqauring both LHS and RHS, (x + 2)^2 = x^2 + 6 ==> x^2 + 4 + 4x = x^2 + 6

• Solving Algebraic Equations for a Given Variable

  39852 Solving Algebraic Equations for a Given Variable I am trying to solve: x^2 + 6x - 10 = 0 Please see the attached file for the complete solution. Thanks for using BrainMass. An equation is solved.

• Why we have graphical and numerical methods for equations

  341393 System of equations: algebraic and graphical method Explain the difference between solving a system of equations by the algebraic method and the graphical method to a sixth grader?

• Solving Algebraic Equations for a Given Variable

  39840 Solving Algebraic Equations for a Given Variable M^3 + 2m^2 - 3m = 0 Since m^3 + 2m^2 - 3m = 0, we have m( m^2 + 2m-3) = 0 So, m( m+3)(m-1) = 0 So, m=0, or m=-3, or m=1 An equation is solved.

• Solving Algebraic Equations for a Given Variable

  44904 Solving Algebraic Equations for a Given Variable : x/4=2+x-3/3 X/4=2+x-3/3 Please see the attached file for the complete solution. Thanks for using BrainMass. An equation is solved. The solution is detailed and well presented.

• Solving Algebraic Equations for a Given Variable

  39851 Solving Algebraic Equations for a Given Variable I am trying to solve an equation using any method.