Explain why 2 and 3/2 cannot be the roots of 2y2 - 7y + 3 = 0© BrainMass Inc. brainmass.com December 24, 2021, 5:05 pm ad1c9bdddf
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If 2 and 3/2 are the roots of a second degree polynomial P(y) we could have written the polynomial as:
P(y) = y^2-2y-3y/2+3
P = (y^2) - (7y/2) + 3
And this is NOT the original polynomial:
Q(y) = 2y^2 - 7y + 3
Thus, 2 and 3/2 are not the roots of Q(x).© BrainMass Inc. brainmass.com December 24, 2021, 5:05 pm ad1c9bdddf>