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1. Find decimal notation for -4/25.
__x_a. -0.16
____b. -0.4
____c. -0.4
____d. -6.25

2. Find the absolute value: -/-6.8/.
____a. -8.6
____b. -6.8
__x_c. 6.8
____d. 8.6

3. Add: -6+12+(-5)+3
____a. -8
____b. 4
____c. 14
_x__d. 26

4. Add: -5/6 + 1/2
__x_a. 4/3
____b. 3/4
____c. -1/3
____d. -1/2

5. Find the opposite, or additive inverse, of 3/4.
____a. -4/3
_x__b. -3/4
____c. 1/4
____d. 4/3

6. Subtract: 3.1 - 9.6
_x__a. -6.5
____b. -5.5
____c. 12.7
____d. 29.76

7. Subtract: 4- (-11).
____a. -6.5
____b. -7
____c. 7
_x__d. 15

8. The lowest recorded temperature in Sweden is -38 C and the lowest recorded temperature in Russia is -68 C. How much higher is the low temperature in Sweden than the low temperature in Russia?
_x__a. 30 C
____b. 38 C
____c. 68 C
____d. 106 C

9. Multiply: -4/5 x (-3/8)
____a. -32/15
____b. -3/10
_x__c. 3/10
____d. 32/15

10. Find the reciprocal of -20.
____a. 400
____b. 20
____c. 1/20
_x__d. -1/20

11. Divide: -5/6 divide 7/12
____a. 10/7
____b. 35/72
____c. -35/72
__x_d. -10/7

12. Simplify: -3(12) - [5(-4) - 2^3]
____a. -64
____b. -24
____c. -8
_x__d. 8

13. Evaluate m/n, when m=10 and n=2
____a. 1/5
_x__b. 5
____c. 12
____d. 20

14. Factor: 18-3n.
____a. 3(6)
____b. 3(6-3n)
_x__c. 3(6-n)
____d. 6(3-n)

15. Solve: 9x = -63
____a. -72
____b. -54
_x__c. -7
____d. 7

16. Solve: 8t + 11 = 7t - 6
____a. 66
____b. 7/8
____c. 1
____d. -17
(this one is difficult to solve)

17. Solve: 0.1p + 2.1 = 4.6p - 1.9 + 0.5p
____a. -1.3
_x__b. 0.04
____c. 0.8
____d. 0.6875

18. Translate to an algebraic expression: Twenty less than some number.
_x__a. x - 20
____b. 20 - x
____c. 20x
____d. x + 20

19. the second angle of a triangle is two times as large as the first. The third angle is 10 degrees more than second angle. Find the measure of the first angle.
____a. 3.6
____b. 34
____c. 38
_x__d. 42.5

20. the perimeter of a rectangular writing pad is 28 inches. The length is 1 inch less than twice the width. Find the width.

____a. 8 inches
_x__b. 7 inches
____c. 6 inches
____d. 5 inches

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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