Mathematics - Algebra
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Find the center and vertices.
graph: x2−4y2=16
Standard Form:
Identify which Conic Section:
Characteristics applicable:
Center:
Vertices:
Asymptotes:
Complete the square, identify the graph of the equation, identify the characteristics
of the conic section and graph: 4x2+25y2−32x+150y+189=0
Standard Form:
Identify which Conic Section:
Characteristics applicable:
Center:
Vertices:
Asymptotes:
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Solution Summary
Complete, neat and step-by-step solutions are provided that assists with solving the precalculus probelm. Graph provided in the attached file.
Solution Preview
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(1) x^2 - 4y^2 = 16
x^2 /16 - y^2 /4 = 1
Hyperbola
Center is (0, 0)
Vertices are at (4, 0) and ...
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