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    Polynomial division

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    PART ONE:

    solve:

    (3n^5 w)^2 /(n^3 w)^0

    A) 0

    B) 9n^7w

    C) 6n^4w

    D) 9n^10w^2

    PART TWO:

    solve:

    9c^7 w^-4 (-d^2)/(15c^3 w^6 (-d)^2)

    A) 3c^4d^2/5w^10

    B) 3c^4/5w^2

    C) 3c^4/5w^10

    D) -3c^4/5w^10

    PART THREE:

    solve:

    5m^-3 /6^-1 m^-2

    A) -5m/6

    B) 30/m

    C) 30m

    D) -5/6m

    PART FOUR:

    solve:

    6+ the square root of 2 / 3- the square root of 2

    A) 18+ the square root of 2 / 9- the square root of 2

    B) 18 + the square root of 2 / 7

    C) 20/7

    D) 20 + 9 times the square root of 2 / 7

    PART FIVE:

    solve:

    18 / 9^3/2

    A) 18^3 times the square root of 81

    B) 2 times the square root of 9 / 9

    C) 2/3

    D) 3/2

    © BrainMass Inc. brainmass.com March 4, 2021, 5:43 pm ad1c9bdddf
    https://brainmass.com/math/basic-algebra/polynomial-division-square-roots-7337

    Solution Preview

    PART ONE:
    (3n^5 w)^2 /(n^3 w)^0 == ??
    Note: I have used * to denote multiplication and make the notations clearer.
    Anything raised to the power of 0 is ALWAYS equal to 1. Therefore the denominator which is ((n^3)*w)^0 = 1. And any entity divided by 1 remains unchanged. So we are left with only the numerator which is
    (3*(n^5)*w)^2.
    In order to evaluate a 'product' raised to a power, we must raise each of the 'members' of the 'product' to the same power. So in our case the 'product' is (3*(n^5)*w). So you raise each member to the same power, which is 2.
    Thus, (3*(n^5)*w)^2 = ...

    Solution Summary

    This shows how to simplify fractions that involve polynomials and square roots.

    $2.49

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