Minimum and maximum surface areas of a cube are found.

I need to find the maximum and minimum surface areas for 2 cubes with a total volume of 432 in^3. No other perameters are specified. I've been able to use common sense to find the max is 432 sq/inches (two 6"^3 cubes) and min is 343.051 sq (one 7.5595"^3 cube and one cube of 0.171"^3). I need help with the equations for the maxima and minima.

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Suppose the two cubes have size x and y inches, respectively, then the volume of the first cube is x^3 and the volumn of the second ...

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Minimum and maximum surface areas of a cube are found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

Surfacearea of a cube. The formula A = 6V^-2/3(-2/3 power) gives the
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Here is the word problem:
A mass of clay of volume 432in^3 is formed into two cubes. What is the minimum possible total surfacearea of the two cubes? What is the maximum?
I have determined the following:
SurfaceArea (SA) = 6a^2
Volume of a cube (V) = a^3
I am not sure how to setup the formula to determine the asked fo

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I am practicing writing pseudocodes and am having issues on the following. Can I get assistance in writing these?
Allow user to enter a value for one edge of a cube. The program calculates the surfacearea of one side of the cube, the surfacearea of the cube, and its volume. The program outputs all the results.
Allow