# Logarithms and Exponents Applications Word Problems

Not what you're looking for?

1. Complete table for savings in which interest is compounded continously.

Initial investment Annual rate Time to double total

$1000 ? ? $2281.88

2. Complete table for radioactive isotope

Isotope Half-life(years) Initial quantity Amt after 1000 years

5715 ? 3.5g

3. The population of P of a city is given by P= 105300 e^0.015t, where t represents the year with t=0 corresponding to 2000. Sketch the graph of this equation.According to this model, in which year will city have population of 150,000?

4. The management at a factory has found that the maximum number of units a worker can produce in a day is 30. the leaning curve for the number of units N produced per day after a new employee has worked t days is given by

After 20 days, a worker produced 19 units in 1 day.

a. Find the learning curve for this worker (first hand the value of k)

b. How many days should pass before this worker is producing 25 units/day?

5. Plot the complex number : 1 - 2i

6. Evaluate expression. Round 3 places

7. Sketch graph of rational function as sketching aids, check for intercepts, symmetry, vertical asymptotes, and horizontal asymptotes

i. ii.

8. approximal real zeros with zoom and trace

##### Purchase this Solution

##### Solution Summary

Logarithms and Exponents Applications Word Problems are solved.

##### Solution Preview

Please see the attached file for the complete solution.

Thanks for using BrainMass.

1. Complete table for savings in which interest is compounded continously.

Initial investment Annual rate Time to double total

$1000 ? ? $2281.88

Solution: There is missing information in this problem. The formula for continuous compound interest is A = P exp(rt) where P is the principal, r is the annual interest rate, t is the time in years, and A is the amount after time t. All we know is A = $2281.88 and P = $1000; so exp(rt) = P/A or rt = ln(P/A).

If we knew r, we could solve for the time to double, d, by solving the equation

2P = A. Since exp(rt) = P/A, this means exp(rt) = 1/2 , or rt = ln(1/2), so d = t = ln(1/2)/r.

2. Complete table for radioactive isotope

Isotope Half-life(years) Initial quantity Amt after 1000 years

5715 ? 3.5g

Solution:

Radioactive substances decay exponentially. That is, the mass M after time t is given by the equation M = I exp(rt) , where r is a decay rate and negative, and I is the initial amount. The half-life ...

##### Purchase this Solution

##### Free BrainMass Quizzes

##### Probability Quiz

Some questions on probability

##### Exponential Expressions

In this quiz, you will have a chance to practice basic terminology of exponential expressions and how to evaluate them.

##### Know Your Linear Equations

Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.

##### Solving quadratic inequalities

This quiz test you on how well you are familiar with solving quadratic inequalities.

##### Geometry - Real Life Application Problems

Understanding of how geometry applies to in real-world contexts