5 log10 (x-2)=11 & 8^-2^-x=431
p=5000(1-4/4+e-0.002x) Find the demand for a price of (a) p=600 and (b) p=400
In problem B: 8^-2^-x=431
There are two options. either to solve for
8^[-2^(-x)]=431 which is ...
The expert examines logarithmic equations for price demand functions.