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Exponential and Logarithm

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The number of bacteria present in a certain culture at time t (measured in hours) is given by P(t)=P0* 2^(0.2t). Time t=0 corresponds to 8.00 A.M. on a particular day and P0 = 2000 is the initial number of bacteria.

Find the number of bacteria present at noon the same day.

How long does it take to have 20,000 bacteria present in the culture?

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Dear student, please refer to the attachment for the solutions.

Given: P(t)=P_0 2^0.2t
P_0=2000

P(t)=2000×2^0.2t
t=0 at 8.00 ...

Solution provided by:
Anwesha Ghosh, MSc
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  • MSc, Osmania University
  • MSc, Indian Institute of Technology - Roorkee (I.I.T.-ROORKEE)
  • BSc, Banaras Hindu University
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