Cyclic Multiplicative Group : Field of Order 2^7
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1. Prove that the multiplicative group of a field of order 2^7 is cyclic.
Note: This problem can be solved in a few lines. Do not construct the field of order 2^7 to solve the problem.
2. Prove that the only subfield of a field of order is a field of order 2.
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Solution Summary
A cyclic multiplicative group is investigated. The solution is detailed and well presented.
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