The fact that Z_n is the kernel of the given inclusion amounts to the existence in G of an element a of order n (so that a generates Z_n). We know that G/<a> is Z_2xZ_2 so it is generated by two elements b,c of order 2 that commute. So G is any such group generated by a,b,c. Let's see what such groups we have:
Because Z_n is normal in G we know that b*a*(b^-1) belongs to Z_n (I denoted by * the group operation, and by b^-1 the inverse ...
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