# Finding the vertices of a hyperbola.

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Find the vertices of the hyperbola with the following equation:

(x-3)^2/25 - (y+4)^2/4 =1

EITHER:

A) (8,-4) and (-2,-4)

B) (5,-4) and (1,-4)

C) (3,-2) and (3,-6)

D) (3,1) and (3,-9)

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#### Solution Preview

(x-3)^2/25 - (y+4)^2/4 =1

In general hyperbola equation is

(x-h)^2/a^2 - (y-k)^2/b^2 =1

So a=5 b=2 h=3 k=-4

(h,k) is the center

So, the ...

#### Solution Summary

The vertices of a hyperbola are found. The equations are examined for y-coordinates.

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