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    Finding the vertices of a hyperbola.

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    Find the vertices of the hyperbola with the following equation:

    (x-3)^2/25 - (y+4)^2/4 =1


    A) (8,-4) and (-2,-4)

    B) (5,-4) and (1,-4)

    C) (3,-2) and (3,-6)

    D) (3,1) and (3,-9)

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    Solution Preview

    (x-3)^2/25 - (y+4)^2/4 =1
    In general hyperbola equation is
    (x-h)^2/a^2 - (y-k)^2/b^2 =1
    So a=5 b=2 h=3 k=-4
    (h,k) is the center
    So, the ...

    Solution Summary

    The vertices of a hyperbola are found. The equations are examined for y-coordinates.