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Different Logic family Gates
(5) Emitter-Coupled Logic (ECL)
Also known as Current Mode Logic (CML), ECL gates are specifically designed to operate at extremely high speeds, by avoiding the "lag" inherent when transistors are allowed to become saturated.
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Spectroscopic Method and Chromatographic Separations
for A
at 450 nm
A = ecl
Or c = A/el = 0.496/ (156.6 M-1cm-1x 1.00cm) = 3.167x10-3 M
At 725
A = ecl
Or c = A/el = 0.875/ (724.87 M-1cm-1x 1.00cm) = 1.207x10-3 M
For B,
at 450 nm
A = ecl
Or c = A/el = 0.496/ (228.68 M-1cm-1x 1.00cm) =
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Absorbance and Concentration of Solution Before/After Dilution
A = ecl
0.055 = (5579 cm-1 M-1)(c)(1 cm)
c = 9.8 uM
Therefore, the diluted solution's concentration was 9.8 micromolar.
However, this was made by a 5:100 (or 1:20) dilution of the stock solution.
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Simplifying a Circuit Diagram
Line A enters a NAND Gate, exits and enters a final NAND Gate. Likewise, Line B enters the same NAND Gate, exits and enters the same final NAND Gate. Line C goes directly to the final NAND Gate.
4.
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Simplifying Circuits and Expressions for Logic Circuits
Simplify the circuit: Line A enters a NOR Gate, exits, and enters a final AND Gate. Likewise, Line B enters the same NOR Gate, exits, and enters the same final NAND Gate. Line C goes directly to the final NAND Gate.
7.
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Simplifying a Circuit
Line A goes into an INVERTER, then into a NAND Gate, then into an OR Gate, then travels into another NOR Gate. Line B travels into the same NAND Gate, then into the same OR Gate, then into the same NOR Gate.
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Electronics - Logic gates
So in our case the NAND gate inputs are "0" and "1" so the output of the NAND gate is "1"
The NOR gate truth table is:
00 1
01 0
10 0
11 0
The NOR (NOT OR) gate is the conjugate of the OR operation, so it will be "1" only if the two inputs
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Understanding absorption coefficient
Beer Lambert Law:
A=elC where A=absorbance, e=extinction coefficient, C=concentration (molar), and l=pathlength (mm)
or
log(I(f)/I(i))=-eCl, where I(f) is the intensity of the light after it passes through the sample and I(i) is the intensity of
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De Morgan's Theorem
Our circuit can now be formed. we need, a NAND gate (for the first term), a NOT gate & OR gate for the second term and finally another AND gate to unite the first and second.