# Stiffness matrices and displacements in spring systems

For the spring system shown in the attached diagram, find:

a) The stiffness matrix for each element

b) The unconstrained global stiffness matrix

c) The constrained (reduced) stiffness matrix

d) The displacements of node 2 and node 3

e) The reaction forces at node 1 and node 4

For the given spring system in the second attachment, find:

a) The stiffness matrix for each element (symbolically)

b) The unconstrained global stiffness matrix (symbolically)

c) The constrained (reduced) stiffness matrix (symbolically)

Take k1 = 100N/mm, k2 = 200N/mm, k3 = 300N/mm, k4 = 400 N/mm, P1 = 1000N, P3 = 3000N

d) The displacements of nodes 1, 2, 3 (numerically)

e) The reaction forces at node 4 and node 5 (numerically)

https://brainmass.com/engineering/mechanical-engineering/stiffness-matrices-displacements-spring-systems-69435

#### Solution Preview

Problem 1

a.) k1 -k1 100 -100

= (stiffness matrix for element 1)

- k1 k1 -100 100

k2 -k2 200 -200

= (stiffness matrix for element 2)

- k2 k2 -200 200

k3 -k3 100 -100

= (stiffness matrix for element 3)

- k3 k3 -100 100

b) k1 -k1 u1 f1ele1

X = (1)

- k1 k1 u2 f2ele1

k2 -k2 u2 f2ele2

X = (2)

- k2 k2 u3 f3ele2

k3 -k3 u3 f3ele3

X = (3)

- k3 k3 u4 f4ele3

P1= f1ele1 = k 1u 1-k1u 2 (4)

P2= f2ele1 + f2ele2 = - k1u1 +u2(k1 +k2) -k2u3 (5)

P3= f3ele2 + f3ele3 = - k2u2 +u3(k2 +k3) -k3u4 (6)

P4 = f4ele3 = k3u4 -k3u3 (7)

The above equations can be represented as

k1 -k1 0 0 u1 P1

- k1 k2 +k1 -k2 0 u2 P2

x = (8)

0 -k2 k2+k3 -k3 u3 P3

0 0 -k3 ...

#### Solution Summary

The solution calculates stiffness matrices for different elements of springs systems as well as displacements and reaction forces.