Rate of Heat Generation

Related BrainMass Solutions

• Electricity: Power dissipated by a resistor

  + rate of heat generation = 0 Or -0.2(T - 298) + 10 = 0 Or -0.2T + 59.6 + 10 = 0 Or T = 69.6/0.2 = 348 K or 75 deg C Power dissipated by a resistor is examined.

• Center Temperature: Electric Current Passed through a Wire

  Solution: Radius of the wire R = 0.001268 m k = 22.5 W/m*K electric resistance of wire Re = 0.126 ohms length L = 0.91 m current I = 200 A Hence rate of heat generation

• power dissipation

  What causes heat generation within electrical devices are determined.

• Heat Loss Calculations for a Martian Surface

  The loss from the sphere is calculated by using the equation relating total heat flow rate, Q, to the temperature difference T, shape factor, and thermal conductance: Q = Sk(T_1 - T_2 ) This solution explains how to interpret the heat transfer situation

• Heat Transfer: a Plane Wall; Find Maximum Temperature in Wall

  The maximum temperature of a plance wal is calculated given volumetric heat generation and the heat transfer coefficient of a fluid.

• Electrical Energy: Center Temperature and Maximum Temperature of a Wall

  Basic concept of this assignment is related to (a) current (b) Resistance (c) Volumetric heat generation In this type of problem we use simple Ohms law Q = I2*R Where R = resistance Solution: Given that in problem Radius of wire r = 0.001268m

• Fire Safety

  It is descriptive because it described how an increase in the heat generation rate can increase the length of the flame and how the growth of the ventilation velocity will shortens the flame length.

• The DC input power, heat generation and maximum thermal resistance of class A and B amplifiers are calculated, and the resulting numbers indicate that a Class A amplifier is an enormous power waster in comparison to a class B amplifier.

  563483 eat generation and maximum thermal resistance of class A and B The DC input power, heat generation and maximum thermal resistance of class A and B amplifiers are calculated.

• Three problems on circuit analysis

  Thus, current through 10 ohm resistor = 2/3 A Rate of heat generation in 10 ohm resistor = I2R = (2/3)2 x 10 = 4.44 J/s Time taken to produce 60 J = 60/4.44 = 13.5 sec Problem 26.64 Let us first simplify the given circuit diagram.