Applied Loads, Young's Modulus, Poisson's Ratio

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  Take Young's modulus for steel to be Y = 2à?1011 Pa.

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  With a force of 200 KN, stress applied on the rod = Force/Area of cross section = F/A A = ПR^2 = П(25/1000)^2 = 1.96 x 10^-3 m^2 Hence, Stress = 200000/(1.96 x 10^-3) = 10.2 x 10^7 N/m^2 Strain produced in the rod = Δl/l Young's modulus